(x-2)^2-6(x+1)=(x-1)(x-2)

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Solution for (x-2)^2-6(x+1)=(x-1)(x-2) equation: 



(x-2)^2-6(x+1)=(x-1)(x-2)

We move all terms to the left:

(x-2)^2-6(x+1)-((x-1)(x-2))=0

We multiply parentheses

(x-2)^2-6x-((x-1)(x-2))-6=0

We multiply parentheses ..

-((+x^2-2x-1x+2))+(x-2)^2-6x-6=0



We calculate terms in parentheses: -((+x^2-2x-1x+2)), so:

(+x^2-2x-1x+2)

We get rid of parentheses

x^2-2x-1x+2

We add all the numbers together, and all the variables

x^2-3x+2

Back to the equation:

-(x^2-3x+2)



We add all the numbers together, and all the variables

-6x-(x^2-3x+2)+(x-2)^2-6=0

We get rid of parentheses

-x^2-6x+3x+(x-2)^2-2-6=0

We add all the numbers together, and all the variables

-1x^2-3x+(x-2)^2-8=0

We move all terms containing x to the left, all other terms to the right

-1x^2-3x+(x-2)^2=8

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